3.1.8 \(\int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n (A+C \sin ^2(e+f x)) \, dx\) [8]

3.1.8.1 Optimal result
3.1.8.2 Mathematica [F]
3.1.8.3 Rubi [A] (verified)
3.1.8.4 Maple [F]
3.1.8.5 Fricas [F]
3.1.8.6 Sympy [F]
3.1.8.7 Maxima [F]
3.1.8.8 Giac [F]
3.1.8.9 Mupad [F(-1)]

3.1.8.1 Optimal result

Integrand size = 38, antiderivative size = 257 \[ \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx=\frac {2^{\frac {1}{2}+n} c (C (1+2 m) (m-n)+(1+m+n) (C (1-m+n)+A (2+m+n))) \cos (e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2} (1+2 m),\frac {1}{2} (1-2 n),\frac {1}{2} (3+2 m),\frac {1}{2} (1+\sin (e+f x))\right ) (1-\sin (e+f x))^{\frac {1}{2}-n} (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{-1+n}}{f (1+2 m) (1+m+n) (2+m+n)}-\frac {C (1+2 m) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n}{f (1+m+n) (2+m+n)}+\frac {C \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{1+n}}{c f (2+m+n)} \]

output
2^(1/2+n)*c*(C*(1+2*m)*(m-n)+(1+m+n)*(C*(1-m+n)+A*(2+m+n)))*cos(f*x+e)*hyp 
ergeom([1/2-n, 1/2+m],[3/2+m],1/2+1/2*sin(f*x+e))*(1-sin(f*x+e))^(1/2-n)*( 
a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^(-1+n)/f/(1+2*m)/(1+m+n)/(2+m+n)-C*(1+2 
*m)*cos(f*x+e)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n/f/(1+m+n)/(2+m+n)+C*c 
os(f*x+e)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^(1+n)/c/f/(2+m+n)
 
3.1.8.2 Mathematica [F]

\[ \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx=\int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx \]

input
Integrate[(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^n*(A + C*Sin[e + f*x 
]^2),x]
 
output
Integrate[(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^n*(A + C*Sin[e + f*x 
]^2), x]
 
3.1.8.3 Rubi [A] (verified)

Time = 1.18 (sec) , antiderivative size = 306, normalized size of antiderivative = 1.19, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.289, Rules used = {3042, 3519, 25, 3042, 3452, 3042, 3224, 3042, 3168, 80, 79}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (a \sin (e+f x)+a)^m \left (A+C \sin ^2(e+f x)\right ) (c-c \sin (e+f x))^n \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int (a \sin (e+f x)+a)^m \left (A+C \sin (e+f x)^2\right ) (c-c \sin (e+f x))^ndx\)

\(\Big \downarrow \) 3519

\(\displaystyle \frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}-\frac {\int -(\sin (e+f x) a+a)^m (c-c \sin (e+f x))^n (a c (C (-m+n+1)+A (m+n+2))+a c C (2 m+1) \sin (e+f x))dx}{a c (m+n+2)}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {\int (\sin (e+f x) a+a)^m (c-c \sin (e+f x))^n (a c (C (-m+n+1)+A (m+n+2))+a c C (2 m+1) \sin (e+f x))dx}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int (\sin (e+f x) a+a)^m (c-c \sin (e+f x))^n (a c (C (-m+n+1)+A (m+n+2))+a c C (2 m+1) \sin (e+f x))dx}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

\(\Big \downarrow \) 3452

\(\displaystyle \frac {\frac {a c ((m+n+1) (A (m+n+2)+C (-m+n+1))+C (2 m+1) (m-n)) \int (\sin (e+f x) a+a)^m (c-c \sin (e+f x))^ndx}{m+n+1}-\frac {a c C (2 m+1) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^n}{f (m+n+1)}}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {a c ((m+n+1) (A (m+n+2)+C (-m+n+1))+C (2 m+1) (m-n)) \int (\sin (e+f x) a+a)^m (c-c \sin (e+f x))^ndx}{m+n+1}-\frac {a c C (2 m+1) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^n}{f (m+n+1)}}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

\(\Big \downarrow \) 3224

\(\displaystyle \frac {\frac {a c ((m+n+1) (A (m+n+2)+C (-m+n+1))+C (2 m+1) (m-n)) \cos ^{-2 m}(e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^m \int \cos ^{2 m}(e+f x) (c-c \sin (e+f x))^{n-m}dx}{m+n+1}-\frac {a c C (2 m+1) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^n}{f (m+n+1)}}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {a c ((m+n+1) (A (m+n+2)+C (-m+n+1))+C (2 m+1) (m-n)) \cos ^{-2 m}(e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^m \int \cos (e+f x)^{2 m} (c-c \sin (e+f x))^{n-m}dx}{m+n+1}-\frac {a c C (2 m+1) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^n}{f (m+n+1)}}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

\(\Big \downarrow \) 3168

\(\displaystyle \frac {\frac {a c^3 ((m+n+1) (A (m+n+2)+C (-m+n+1))+C (2 m+1) (m-n)) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{\frac {1}{2} (-2 m-1)+m} (c \sin (e+f x)+c)^{\frac {1}{2} (-2 m-1)} \int (c-c \sin (e+f x))^{\frac {1}{2} (2 n-1)} (\sin (e+f x) c+c)^{\frac {1}{2} (2 m-1)}d\sin (e+f x)}{f (m+n+1)}-\frac {a c C (2 m+1) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^n}{f (m+n+1)}}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

\(\Big \downarrow \) 80

\(\displaystyle \frac {\frac {a c^3 2^{n-\frac {1}{2}} ((m+n+1) (A (m+n+2)+C (-m+n+1))+C (2 m+1) (m-n)) \cos (e+f x) (1-\sin (e+f x))^{\frac {1}{2}-n} (a \sin (e+f x)+a)^m (c \sin (e+f x)+c)^{\frac {1}{2} (-2 m-1)} (c-c \sin (e+f x))^{\frac {1}{2} (-2 m-1)+m+n-\frac {1}{2}} \int \left (\frac {1}{2}-\frac {1}{2} \sin (e+f x)\right )^{\frac {1}{2} (2 n-1)} (\sin (e+f x) c+c)^{\frac {1}{2} (2 m-1)}d\sin (e+f x)}{f (m+n+1)}-\frac {a c C (2 m+1) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^n}{f (m+n+1)}}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

\(\Big \downarrow \) 79

\(\displaystyle \frac {\frac {a c^2 2^{n+\frac {1}{2}} ((m+n+1) (A (m+n+2)+C (-m+n+1))+C (2 m+1) (m-n)) \cos (e+f x) (1-\sin (e+f x))^{\frac {1}{2}-n} (a \sin (e+f x)+a)^m (c \sin (e+f x)+c)^{\frac {1}{2} (-2 m-1)+\frac {1}{2} (2 m+1)} (c-c \sin (e+f x))^{\frac {1}{2} (-2 m-1)+m+n-\frac {1}{2}} \operatorname {Hypergeometric2F1}\left (\frac {1}{2} (2 m+1),\frac {1}{2} (1-2 n),\frac {1}{2} (2 m+3),\frac {1}{2} (\sin (e+f x)+1)\right )}{f (2 m+1) (m+n+1)}-\frac {a c C (2 m+1) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^n}{f (m+n+1)}}{a c (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)}\)

input
Int[(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^n*(A + C*Sin[e + f*x]^2),x 
]
 
output
(C*Cos[e + f*x]*(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^(1 + n))/(c*f* 
(2 + m + n)) + (-((a*c*C*(1 + 2*m)*Cos[e + f*x]*(a + a*Sin[e + f*x])^m*(c 
- c*Sin[e + f*x])^n)/(f*(1 + m + n))) + (2^(1/2 + n)*a*c^2*(C*(1 + 2*m)*(m 
 - n) + (1 + m + n)*(C*(1 - m + n) + A*(2 + m + n)))*Cos[e + f*x]*Hypergeo 
metric2F1[(1 + 2*m)/2, (1 - 2*n)/2, (3 + 2*m)/2, (1 + Sin[e + f*x])/2]*(1 
- Sin[e + f*x])^(1/2 - n)*(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^(-1/ 
2 + (-1 - 2*m)/2 + m + n)*(c + c*Sin[e + f*x])^((-1 - 2*m)/2 + (1 + 2*m)/2 
))/(f*(1 + 2*m)*(1 + m + n)))/(a*c*(2 + m + n))
 

3.1.8.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 79
Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(( 
a + b*x)^(m + 1)/(b*(m + 1)*(b/(b*c - a*d))^n))*Hypergeometric2F1[-n, m + 1 
, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m, n}, x] 
&&  !IntegerQ[m] &&  !IntegerQ[n] && GtQ[b/(b*c - a*d), 0] && (RationalQ[m] 
 ||  !(RationalQ[n] && GtQ[-d/(b*c - a*d), 0]))
 

rule 80
Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(c 
 + d*x)^FracPart[n]/((b/(b*c - a*d))^IntPart[n]*(b*((c + d*x)/(b*c - a*d))) 
^FracPart[n])   Int[(a + b*x)^m*Simp[b*(c/(b*c - a*d)) + b*d*(x/(b*c - a*d) 
), x]^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] &&  !IntegerQ[m] &&  !Integ 
erQ[n] && (RationalQ[m] ||  !SimplerQ[n + 1, m + 1])
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3168
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x 
_)])^(m_.), x_Symbol] :> Simp[a^2*((g*Cos[e + f*x])^(p + 1)/(f*g*(a + b*Sin 
[e + f*x])^((p + 1)/2)*(a - b*Sin[e + f*x])^((p + 1)/2)))   Subst[Int[(a + 
b*x)^(m + (p - 1)/2)*(a - b*x)^((p - 1)/2), x], x, Sin[e + f*x]], x] /; Fre 
eQ[{a, b, e, f, g, m, p}, x] && EqQ[a^2 - b^2, 0] &&  !IntegerQ[m]
 

rule 3224
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*sin[(e_.) + ( 
f_.)*(x_)])^(n_), x_Symbol] :> Simp[a^IntPart[m]*c^IntPart[m]*(a + b*Sin[e 
+ f*x])^FracPart[m]*((c + d*Sin[e + f*x])^FracPart[m]/Cos[e + f*x]^(2*FracP 
art[m]))   Int[Cos[e + f*x]^(2*m)*(c + d*Sin[e + f*x])^(n - m), x], x] /; F 
reeQ[{a, b, c, d, e, f, m, n}, x] && EqQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] 
 && (FractionQ[m] ||  !FractionQ[n])
 

rule 3452
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + 
 (f_.)*(x_)])*((c_) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Sim 
p[(-B)*Cos[e + f*x]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^n/(f*(m + 
n + 1))), x] - Simp[(B*c*(m - n) - A*d*(m + n + 1))/(d*(m + n + 1))   Int[( 
a + b*Sin[e + f*x])^m*(c + d*Sin[e + f*x])^n, x], x] /; FreeQ[{a, b, c, d, 
e, f, A, B, m, n}, x] && EqQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] &&  !LtQ[m, 
 -2^(-1)] && NeQ[m + n + 1, 0]
 

rule 3519
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + 
 (f_.)*(x_)])^(n_.)*((A_.) + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> 
 Simp[(-C)*Cos[e + f*x]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(n + 1 
)/(d*f*(m + n + 2))), x] + Simp[1/(b*d*(m + n + 2))   Int[(a + b*Sin[e + f* 
x])^m*(c + d*Sin[e + f*x])^n*Simp[A*b*d*(m + n + 2) + C*(a*c*m + b*d*(n + 1 
)) - b*c*C*(2*m + 1)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A 
, C, m, n}, x] && EqQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] &&  !LtQ[m, -2^(-1 
)] && NeQ[m + n + 2, 0]
 
3.1.8.4 Maple [F]

\[\int \left (a +a \sin \left (f x +e \right )\right )^{m} \left (c -c \sin \left (f x +e \right )\right )^{n} \left (A +C \left (\sin ^{2}\left (f x +e \right )\right )\right )d x\]

input
int((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x)
 
output
int((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x)
 
3.1.8.5 Fricas [F]

\[ \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx=\int { {\left (C \sin \left (f x + e\right )^{2} + A\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} {\left (-c \sin \left (f x + e\right ) + c\right )}^{n} \,d x } \]

input
integrate((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x, algo 
rithm="fricas")
 
output
integral(-(C*cos(f*x + e)^2 - A - C)*(a*sin(f*x + e) + a)^m*(-c*sin(f*x + 
e) + c)^n, x)
 
3.1.8.6 Sympy [F]

\[ \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx=\int \left (a \left (\sin {\left (e + f x \right )} + 1\right )\right )^{m} \left (- c \left (\sin {\left (e + f x \right )} - 1\right )\right )^{n} \left (A + C \sin ^{2}{\left (e + f x \right )}\right )\, dx \]

input
integrate((a+a*sin(f*x+e))**m*(c-c*sin(f*x+e))**n*(A+C*sin(f*x+e)**2),x)
 
output
Integral((a*(sin(e + f*x) + 1))**m*(-c*(sin(e + f*x) - 1))**n*(A + C*sin(e 
 + f*x)**2), x)
 
3.1.8.7 Maxima [F]

\[ \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx=\int { {\left (C \sin \left (f x + e\right )^{2} + A\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} {\left (-c \sin \left (f x + e\right ) + c\right )}^{n} \,d x } \]

input
integrate((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x, algo 
rithm="maxima")
 
output
integrate((C*sin(f*x + e)^2 + A)*(a*sin(f*x + e) + a)^m*(-c*sin(f*x + e) + 
 c)^n, x)
 
3.1.8.8 Giac [F]

\[ \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx=\int { {\left (C \sin \left (f x + e\right )^{2} + A\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} {\left (-c \sin \left (f x + e\right ) + c\right )}^{n} \,d x } \]

input
integrate((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x, algo 
rithm="giac")
 
output
integrate((C*sin(f*x + e)^2 + A)*(a*sin(f*x + e) + a)^m*(-c*sin(f*x + e) + 
 c)^n, x)
 
3.1.8.9 Mupad [F(-1)]

Timed out. \[ \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx=\int \left (C\,{\sin \left (e+f\,x\right )}^2+A\right )\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,{\left (c-c\,\sin \left (e+f\,x\right )\right )}^n \,d x \]

input
int((A + C*sin(e + f*x)^2)*(a + a*sin(e + f*x))^m*(c - c*sin(e + f*x))^n,x 
)
 
output
int((A + C*sin(e + f*x)^2)*(a + a*sin(e + f*x))^m*(c - c*sin(e + f*x))^n, 
x)